This calculation shows that burning grams of methane

Since the question is incomplete but i just answered a question exactly like it with more information i will give that answer here, i hope it you out:
formula for heat change:   q = mcδtwhere 
q = the heat addedm = massc = specific heatδt=  (tf - to in absolute temperature) 
note: in this case subtracting the final and initial temperature in kelvin or celsius will not make a difference)
we add everything into the formula:   δt  = t(final) - t(original)
δt  = 36.65 - 24.85δt  = 11.8° cso the change in temperature is 11.8 degrees 

q = 41.11x  4.319 x 11.8 
q= 2095.13 heat of combustion of methane.
it shows that burning 41.11g of methane gives of 2095.13 joules of energy

Copper, silver, aluminum, cobalt, chromium, mercury 

What do you mean by that? like the contents? the thc level?