An unknown compound with a molar mass of 155.06 g/mol consists of 46.47% c, 7.80% h, and 45.72% cl. find the molecular formula for the compound. c6h12cl2 chcl c9h18cl3 c6h12cl

The emperical formula of compound is calculated as:

Atomic ratio for Carbon, :

Atomic ratio for Hydrogen, :

Atomic ratio for Chlorine, :

The simplest ratio is:

For Carbon =

For Hydrogen =

For Chlorine =

So, the emperical formula of the compound is .

For determining the molecular formula:

Molar Mass =

Emperical Formula Mass =

Substituting the values,

Since, so, the molecular formula is:

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