How many grams of glucose would be present in one liter of a 1 m solution of glucose?

             Mass  =  180 g

Solution:

Step 1: Calculate Moles using following Formula,

                                   Molarity  =  Moles ÷ Volume

Solving for Moles,

                                  Mole  =  Molarity × Volume

Putting values,

                                  Mole  =  1 mol.L⁻¹ × 1 L

                                  Mole  =  1 moles

Step 2: Calculate mass using following formula,

                                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                                  Mass  =  Moles × M.Mass

Putting Values,

                                  Mass  =  1 mol × 180 g.mol⁻¹

                                  Mass  =  180 g

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year