If 25.8 ml of agno3 solution is needed to precipitate all the cl- ions in a 785 mg sample of kcl (forming agcl) what is the molarity of the agno3 solution

Answer : The molarity of the AgNO₃ solution is 0.408 M

Answer :

The balanced chemical equation for the reaction between KCl and AgNO₃ is given below.

Step 1 : Find moles of KCl.

The mass of KCl is given as 785 mg. Let's convert this to grams.

The molar mass of KCl is 74.55 g/mol

The moles of KCl can be calculated as,

We have 0.0105 mol KCl

Step 2 : Find moles of AgNO₃.

The mole ratio of KCl and AgNO₃ is 1 : 1.

The moles of AgNO₃ can be calculated using this mole ratio.

We have 0.0105 mol AgNO₃.

Step 3 : Use molarity formula.

The molarity of AgNO₃ can be calculated as,

The volume of AgNO₃ solution is 25.8 mL which is 0.0258 L.

The molarity of the AgNO₃ solution is 0.408 M.

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.