Acar moves 5 km to the east, then 3 km to the north, and then 1 km to the east again. what is his displacement from his original position? write your answer to the nearest tenth. don't forget to include direction.

The displacement is 6.7 km to the northeast.

Displacement = 5 km + 1 km = 6 km to the east and 3 km to the north.

The net displacement is the hypotenuse of a right-angled triangle with sides

6 km and 3 km.

According to Pythagoras’ Theorem,

a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the other two sides.

c^2 = (6 km)^2 + (3km)^2 = 36 km^2 + 9 km^2 = 45 km^2

c = √(45 km^2) = 6.7 km NE

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.