When added to a sealed flask and heated, 6.0g of carbon and 16.0 g of oxygen react to form22.0 g of carbon dioxide. how much carbondioxide is formed when 12.0 g of carbon isreacted with 100.0 g of oxygen?

44.0g of CO2 is formed.

Explanation:

Using law of definite proportion,

(6.0g/22)CO2 =0.2727g of Carbon

(12/22)CO2= 0.5455g of Oxygen

(12g of carbon)/( xg of CO2)= 0.2727

Xg of CO2= 12g/0.2727 =44.0g

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8