How many cations are there in 40.0 g of sodium phosphate?

Formula of sodium phosphate is

The molar mass of compound,

Mass of compound, m = 30 g

Number of mol is mass of compound divided by its molar mass as below:

n = m /M

Mole can be expressed as:

Number of particle /N_A = n = 0.182 mol

Number of particle

As 3 sodium or cation are present in compound

Thus, 3.3 * 10^23  cation are present in 30 g sodium phosphate

There are 4.41 × 10²³ cations in 40.0 g of sodium phosphate.

First, we will convert 40.0 g of Na₃PO₄ to moles using its molar mass (163.94 g/mol).

Then, we will convert 0.244 moles to molecules using Avogadro's number: there are 6.02 × 10²³ molecules of Na₃PO₄ in 1 mole of molecules of Na₃PO₄.

Sodium phosphate is a strong electrolyte that dissociates according to the following equation.

Na₃PO₄ ⇒ 3 Na⁺ + PO₄³⁻

As we can see, there are 3 Na⁺ cations per molecule of Na₃PO₄. The number of  Na⁺ cations in 1.47 × 10²³ molecules of Na₃PO₄ are:

There are 4.41 × 10²³ cations in 40.0 g of sodium phosphate.

You can learn more about Avogadro's number here:

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.