How many moles of n2o5 will remain after 7.0 min ?

The first-order rate constant for the decomposition of N2O5  

, 2N2O5(g)--> 4NO2(g)+O2(g)  

at 70 C is 6.82x10^-3s-1. Suppose we start with 2.74×10−2 mol of N2O5(g) in a volume of 2.3L .  

How many moles of N2O5 will remain?

The Integrate rate law can be shown as:

K is constant =

t is time

[A_0] is the intial mol  

Molarity = [A_0] = n / V (liter) = 0.0274 /2.3 L = 0.0119 M

1243 .76 = log (0.0119) – log [A]

Thus , remaining amount of solute after 7 minute is 0.0072 mol /L