The human body obtains 915 kj of energy from a candy bar. part a if this energy were used to vaporize water at 100.0 ∘c, how much water (in liters) could be vaporized? (assume the density of water is 1.00 g/ml

Given the energy obtained by the human body from a candy bar = 915 kJ

Energy required to vaporize 1 g of water at it's boiling point is referred to as heat of vaporization of water.

The heat of vaporization of water = 2260 J/g

Mass of water that can be vaporized by 915 kJ of heat =

Density of water = 1 g/mL

Converting mass to volume in L of 405 g water:

Therefore, 0.405 L of water can be vaporized

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.