The american dental association recommends that an adult female should consume 3.0 mg of fluoride (f−) per day to prevent tooth decay. part a if the fluoride is consumed as sodium fluoride (45.24% f), what amount of sodium fluoride contains the recommended amount of fluoride?

An adult female should consume 6.6 mg of NaF to acquire 3.0 mg of F⁻.

The recommended consumption of F⁻ for an adult female is 3.0 mg of F⁻.

Fluoride is usually consumed as NaF, whose content in mass is 45.24% F⁻. That is, there are 45.24 mg of F⁻ every 100 g of NaF.

The mass of NaF that contains 3.0 mg of F⁻ is:

An adult female should consume 6.6 mg of NaF to acquire 3.0 mg of F⁻.

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Answer  6.6 mg of sodium fluoride contains the recommended amount of fluoride

Explanation :

We have been given that the daily requirement of fluoride is 3.0 mg.

And sodium fluoride contains 45.24% of F. That means 100 grams of sodium fluoride will have 45.24 grams of fluoride.

We can also say that 100 mg of sodium fluoride will have 45.24 mg of fluoride.

Let us use this as a conversion factor to find out how much sodium fluoride will provide the daily required amount o fluoride.

The equation can be set up as follows.

6.6 mg of sodium fluoride contains the recommended amount of fluoride

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3