What is the volume of 0.98 mol oxygen (o2) gas at 275 k and a pressure of 2.0 atm? (the universal gas constant is 0.0821 l*atm/mol*k)

There exists a law of perfect gases which is written in the form PV = nRT, where P is the pressure of a gas (in pascals), V the volume occupied by the gas (in m3), n the quantity of material ( in moles), R is the universal constant of the perfect gases, and T is the temperature (in kelvins).

First, we should convert the values if necessary (in this case it is not), and the result (the volume will be in liters (according to the universal gas constant).

PV = nRT

V = nRT / P = 0.98 0.0821 275 / 2 = 11.06 L of Oxygen gas

The volume is 11.06 Liters of Oxygen gas

the answer is b. dilution

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b