One mole (mol) of glucose (molecular mass = 180 daltons) is a 180 × 1023 molecules of glucose. b 1 kg of glucose dissolved in 1 l of solution. c the largest amount of glucose that can be dissolved in 1 l of solution. d 180 kilograms of glucose. e both 180 grams of glucose and 6.02 × 1023 molecules of glucose.

Answer;

E. both 180 grams of glucose and 6.02 × 1023 molecules of glucose

Explanation;

-One mole of any substance contains 6.02 ×10^23 particles, which is known as the Avagadro's contant.

-Avogadro's number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.022140857 × 1023. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.

-Therefore; 1 mole of glucose contains 6.02 ×10^23 molecules which is equivalent to a mass of 180 g.

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.