The molecular formula mass of this compound is 120 amu . what are the subscripts in the actual molecular formula? enter the subscripts for c, h, and o

The simplest formula i.e, empirical formula  of the organic molecule having molar mass 120 can be assumed to be CH₂O, because if we consider the simplest formula as CHO then empirical formula mass becomes (12+1+16)=29 which can never be possible if molecular mass  of the compound is 120 as molecular formula can not be fractional. If empirical formula is CH₂O, then empirical formula mass becomes (12+2+16)=30 by which 120 is divisible. So, the molecular formula is considered as- (CH₂O)ₓ, where x= positive integer.

Mass of (CH₂O)ₓ=120, which indicates (12+2+16) X x =120

So, 30x =120, x=4.Hence the molecular formula is C₄H₈O₄.

Subscript for C=4, H=8, O=4.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer