Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka 4.76) of (a) 2: 1; (b) 1: 3; (c) 5: 1; (d) 1: 1; (e) 1: 10

According to Hasselbach-Henderson equation:

Here, is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is and acid is thus, Hasselbach-Henderson equation will be as follows:

...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

Also,

Putting the values in equation (1),

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

Also,

Putting the values in equation (1),

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

Also,

Putting the values in equation (1),

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

Also,

Putting the values in equation (1),

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

Also,

Putting the values in equation (1),

Therefore, pH of solution is 3.76.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→