How many moles of mgs2o3 are in 193 g of the compound?

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

they include patterns; cause and effect; scale, proportion, and quantity; systems and system models; energy and matter; structure and function; and stability and change.

can i get the brainiest answer

i answered it first