If 4 dooms = 7 farzes, 1 bing = 2 wots, 2 zots = 3 dooms, and 9 farzes = 4 bings, then 3 zots = ? wots.

3 zots = 7 wots

3 zots × (3 dooms/2 zots) = ⁹/₂ dooms

⁹/₂ dooms × (7 farzes/4 dooms) = ⁶³/₈ farzes

⁶³/₈  farzes × (4 bings/9 farzes) = ⁷/₂ bings

⁷/₂ bings × (2 wots/1 bing) = 7 wots

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

43.452

step-by-step explanation:

284 times .153 = 43.452