What is the molality of a solution containing 8.0 grams of solute in 0.50 kg of solvent? (molar mass of solute = 24 g)

The molal concentration of the solution is 0.67 mol/kg.

The formula for molal concentration (b) is

b = moles of solute/kilograms of solvent.

Moles of solute = 8.0 g × (1 mol/24 g) = 0.333 mol

b = 0.333 mol/0.50 kg = 0.67 mol/kg

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.