The density of lead is 1.135×104 kg/m3. what is the mass of a rectangular ingot of lead with dimensions 2.00 cm × 2.00 cm × 0.850 dm?

              Mass =  385.9 g

Data Given:

                  Density =  1.135 × 10⁴ Kg/m³  =  11.35 g/cm³

                  Volume  =  2.0 cm × 2.0 cm × 0.850 dm

As (1 decimeter  =  10 Centimeter) So,

                  Volume  =  2.0 cm × 2.0 cm × 8.5 cm  =  34 cm³

Formula Used:

                       Density  =  Mass ÷ Volume

Solving for Mass,

                        Mass  =  Density × Volume

                        Mass  =  11.35 g/cm³ × 34 cm³

                        Mass =  385.9 g

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

it should be all of them because it asks if you included all of those in your answer

explanation: