Determine the enthalpy for the reaction s+0_2 --> so_2

ΔH = -296.7 kJ

We have two equations:

(1) 2S +3O₂ → 2SO₃; ΔH = -791.6 kJ

(2) 2SO₂ + O₂ → 2SO₃; ΔH = -198.2 kJ

From these, we must devise the target equation:  

(3) S + O₂ → SO₂; ΔH = ?

The target equation has 1S on the left, so you divide equation (1) by 2.

When you halve an equation, you halve its ΔH.

(4) S + ³/₂O₂ → SO₃; ΔH = -395.8 kJ

Equation (4) has 1SO₃ on the right, and that is not in the target equation.

You need an equation with 1SO₃ on the left.

Reverse Equation (2) and divide it by 2.

When you reverse an equation, you reverse the sign of its ΔH.

(5) SO₃ → SO₂ + ½O₂; ΔH = +99.1 kJ

Now, you add equations (4) and (5), cancelling species that appear on opposite sides of the reaction arrows.

When you add equations, you add their ΔH values.

We get the target equation (3):

(4) S + ³/₂O₂ → SO₃; _ΔH = -395.8 kJ

(5) SO₃ → SO₂ + ½O₂; ΔH = +99.1 kJ

(3) S + O₂ → SO₂; __ΔH = -296.7 kJ

no, i was listening to water by schoolboy q while and i saw this question

explenation:

water isn't wet. wetness is a description of our experience of water; what happens to us when we come into contact with water in such a way that it impinges on our state of being. we, or our possessions, 'get wet'. a less impinging sense experience of water is that it is cold or warm, while visual experience tells us that it is green or blue or muddy or fast-flowing. we learn by experience that a sensation of wetness is associated with water: 'there must be a leak/i must have sat in something.'