Using the balanced chemical reaction below, how many grams of copper (cu) metal can be obtained from 1.00 kg of copper ore (cu3fes3)? 2cu3fes3 (s) + 7o2 (g) ; → 6cu (s) + 2feo (s) + 6so2 (g)

Answer : Mass of copper (Cu) metal obtained = 556.281 g

Solution : Given,

Mass of copper ore = 1 Kg = 1000 g

From the periodic table, the molar mass of copper and copper ore are

Molar mass of copper = 63.546 g/mole

Molar mass of copper ore, = 342.678 g/mole

First we have to calculate the number of moles of copper ore,

Moles of   = = = 2.918 moles

The balanced chemical reaction is :

From this chemical reaction, we conclude that

2 moles of gives          →     6 moles of Cu

2.918 moles of gives   →      

                                                           = 8.754 moles

Thus, the Moles of copper (Cu) = 8.754 moles

Now, calculate the Mass of copper (Cu).

Mass of copper (Cu) = Moles of copper (Cu) × Molar mass of copper (Cu)

                                  = 8.757 moles × 63.546 g/moles

                                  = 556.281 g                                

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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