What mass of co is needed to react completely with 55.0 g of fe2o3 in the reaction: fe2o3(s) + co(g) → fe(s) + co2(g)?

the balanced equation for the reaction is as follows

Fe₂O₃ + 3CO ---> 2Fe + 3CO₂

stoichiometry of Fe₂O₃ to CO is 1:3

mass of Fe₂O₃ reacted - 55.0 g

therefore number of Fe₂O₃ moles reacted - 55.0 g / 159.7 g/mol = 0.344 mol

according to molar ratio

number of CO moles needed is 3 x number of Fe₂O₃ reacted

therefore number of CO moles required - 3 x 0.344 mol = 1.032 mol

mass of CO required - 1.032 mol x 28 g/mol = 28.9 g

28.9 g CO

Explanation: I just took the quiz and it was correct:)

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