What organic product would be formed from the reaction of 1-bromo-2-methylpropane (isobutyl bromide), (ch3)2chch2br, with mg, et2o, then , then h3o+?

The reaction of 1-bromo-2-methylpropane (isobutyl bromide), , with , and results in the formation of an adduct of formula known as grignard reagent, an organometallic reagent, which on reacting with results in the formation of isobutane.

The reaction is shown in the image.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.