Calculate the mass of silver chloride required to plate 265 mg of pure silver.

0.35215 grams of silver chloride required to plate 265 mg of pure silver.

Explanation:

Mass of silver = 265 mg = 0.265 g

Moles of silver =

According to reaction, 2 moles of silver are obtained from 2 moles of silver chloride.

Then 0.002454 moles of silver will be obtained from :

of silver chloride

Mass of 0.002454 moles of silver chloride:

= 0.002454 mol × 143.5 g/mol = 0.35215 g

0.35215 grams of silver chloride required to plate 265 mg of pure silver.

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