How many ions are present in 30.0 ml of 0.600 m na2co3 solution?

Concentration of Na2CO3 = 0.600 M

Volume of Na2CO3 = 30.0 ml = 0.030 L

Molarity = moles of solute/volume of solution

Now,

moles of Na2CO3 = M * V = 0.600*0.030 = 0.018 moles

Na2CO3 ↔ 2Na^+ + CO3^2-

As per stoichiometry:

1 mole of Na2CO3 produces 2 moles of Na+ ions

Therefore, 0.018 moles of Na2CO3 would dissociate to give: 2*0.018 = 0.036 moles of Na+ ions.

Now,

1 mole of Na+ has 6.023 * 10^23 ions

therefore, 0.036 moles of Na+ would correspond to:

= 0.036 * 6.023 * 10^ 23 = 2.17 *10^22 Na+ ions

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.