Consider the formation of hcn by the reaction of nacn (sodium cyanide) with an acid such as h2so4 (sulfuric acid): 2nacn(s)+h2so4(aq)âna2so4(aq)+2hcn( g) what mass of nacn gives the lethal dose in the room?

18.0 g

Explanation:

There is some info missing. I think this is the original question.

Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately 300 mg HCN per kilogram of air when inhaled. The density of air at 26 °C is 1.18 kg/m³.

Consider the formation of HCN by the reaction of NaCN (sodium cyanide) with an acid such as H₂SO₄ (sulfuric acid):

2 NaCN(s) + H₂SO₄(aq) → Na₂SO₄(aq) + 2 HCN(g)

What mass of NaCN gives the lethal dose in the 28.0 m³ room? Express your answer to three significant figures and include the appropriate units.

The density of air is 1.18 kg/m³. The mass represented by 28 m³ is:

28.0 m³ × (1.18 kg/m³) = 33.0 kg

The lethal dose is approximately 300 mg HCN per kilogram of air. The lethal dose of HCN in 33.0 kg of air is:

33.0 kg air × (300 mg HCN / 1 kg air) = 9900 mg HCN = 9.90 g HCN

From the balanced equation, we can establish the following relations:

The mass of NaCN that produces 9.90 g of HCN is:

points

explanation:

i believe the answer is three water molecules