There are two different substances with the formula c5h10 that contain a 5-carbon chain. draw them.

Explanation:

Above Formula has C5H10.

So Calculated Hydrogen =  12

    The actual hydrogens =  10

                       difference = 12-10 = 2

Degree of Unsaturation = 2/2 = 1

So there is possibility of one double bond.        

the first point, i am pretty sure.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer