The equilibrium constant for the equilibrium, 3a+ 2b ↔ 2d + e, is 4.22 x 10-3  . what is the equilibrium constant for the equilibrium: d + (1/2)e ↔ (3/2)a + b? 2.1110-3237-2.1110-315.4

Option D: 15.4

There are following rules for manipulating equilibrium constant:

1. On adding two equilibrium reactions, their equilibrium constant gets multiplied.

For example:

On adding two reactions,

2. On subtracting two equilibrium reactions, their equilibrium constant gets divided.

For example:

On subtracting two reactions,

Or,

3. If an equilibrium reaction is multiplied by any constant, it goes to the power of its equilibrium constant.

For example:

Thus,

4. On reversing an equilibrium reaction, the equilibrium constant of reversed reaction becomes inverse of the original value.

For example:

Thus,

Now, the given equilibrium reaction is as follows:

To get the desired reaction, first reverse the above reaction as follows:

Now, multiply the above reaction with 1/2,

Thus,

Therefore, equilibrium constant for the resultant reaction is 15.4 that is option D.

chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. these processes are called chemical reactions and, in general, are not reversible except by further chemical reactions. some reactions produce heat and are called exothermic reactions and others may require heat to enable the reaction to occur, which are called endothermic reactions. understanding chemical changes is a major part of the science of chemistry.