The freezing point of benzene c6h6 is 5.50°c at 1 atmosphere. a nonvolatile, nonelectrolyte that dissolves in benzene is tnt (trinitrotoluene). how many grams of tnt, c7h5n3o6 (227.1 g/mol), must be dissolved in 297.0 grams of benzene to reduce the freezing point by 0.500°c ?

The amount required in grams to reduce the freezing point by 0.500 degree Celsius will be 6.58 g.

Solution: equation to calculate depression in freezing point

given: = 0.500°C

=  for benzene is 5.12

m=?

y= TNT amount (in grams) required

now according to formula:

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.