How much heat is needed warm 65.34 g of water from 18.43 to 21.75

Given that  

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

)

= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C

= 907.63  J  

= 0.908 KJ

And  

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J =216.78  cal

Or0.218 kcal  

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.

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