Complete the following radioactive decay problem. 210/84 po --> 206/82 pb + / __

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb +  

Your equation is:  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + ?

It becomes easier to balance the equation if we replace the "?" with an element symbol _x^yZ.  

Then the equation becomes  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb +_x^yZ

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Sum of superscripts: 210 = 206 + y, so y =4.  

Sum of subscripts: 84 = 82 + x, so x = 2.

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb +

We should recall that is an α particle.

Thus, the equation represents the α decay of polonium-210 to lead-206.

The nuclear equation is  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb +

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

you did not give any options thus this is the best answer i can give to you with this little information you have given

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