Chemistry, 07.07.2019 22:30 NeonPlaySword

What are the trends and exceptions to the trends in electron affinity? check all that apply. the electron affinities of the elements in group 17 are larger (more negative) than the elements in group 1. electron affinities increase (become more negative) down a group. elements in group 14 have larger (more negative) electron affinities than elements in group 15. elements in group 2 have very large electron affinities.

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Answer from: Artemis3821

the correct answers are:

1) The electron affinities of the elements in Group 17 are larger (more negative) than the elements in Group 1.

3) Elements in Group 14 have larger (more negative) electron affinities than elements in Group 15.

Answer from: jjau834

Explanation:

When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.

Smaller is the size of an atom more readily an electron will be gained by it because of strong force of attraction exerted by its nucleus towards the electron.

So, on moving down a group there will occur a decrease in electron affinity of the atoms. Also, size of atoms decreases from left to right in a periodic table. Therefore, electron affinity will also increase on moving from left to right.

As elements of group 15 are half filled so, they are more stable in nature and have slightly less electron affinity as compared to group 14 elements.

Thus, we can conclude that the trends and exceptions to the trends in electron affinity are as follows.

The electron affinities of the elements in Group 17 are larger (more negative) than the elements in Group 1.Elements in Group 14 have larger (more negative) electron affinities than elements in Group 15.

Answer from: Quest

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

$^{222}_{86} rn+ ^{4}_{2} he$ →

Answer from: Quest

ill try to . no promises tho.

explanation:

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What are the trends and exceptions to the trends in electron affinity? check all that apply. the el...

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