Avolleyball is full of pressurized air. the air temperature is 24.6˚c. the volleyball’s absolute pressure is 130.75 kilopascals, and its volume is 5.27 liters. how many moles of air are inside the volleyball? a. 0.278 mol b. 3.37 mol c. 3.59 mol d. 25.2 mol e. 28.0 mol

             0.278 mol

Data Given:

                   Pressure  =  P  =  130.75 kPa  =  1.29 atm

                   Volume  =  V  =  5.27 L

                   Temperature  =  T  =  24.6 °C  =  297.75 K

                   Gas Constant  =  R  =  0.08215 atm.L.mol⁻¹.K⁻¹

Formula Used:

                   P V  =  n R T

Solving for "n",

                   n  =  P V / R T

Putting values,

             n  =  (1.29 atm × 5.27 L) ÷ (0.08215 atm.L.mol⁻¹.K⁻¹ × 297.75 K)

             n =  0.277 moles

the answer would be b i believe