If 1200 j of heat were absorbed by a 25 g block of iron, by how much would the temperature of the iron increase?

m = mass of the block of iron = 25 g

Q = heat absorbed by the block of iron = 1200 J

ΔT = increase in the temperature of iron due to heat absorbed = ?

c = specific heat of block of iron = 0.450 J/(g C)

Heat absorbed by the block of iron is given as

Q = m c ΔT

inserting the values in the above formula

1200 = 25 (0.450) ΔT

1200 = (11.25) ΔT

ΔT = 1200/11.25

ΔT = 106.67 C

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