How many grams of water can be heated from 5.0∘c to 37.0∘c with 20.0j of heat? the specific heat of water is 4.184j/g∘c.

-  mass of water is 0.15 g.

Solution:- This problem is based on the formula:

where, q is the heat energy, m is mass, is specific heat and is change in temperature.

 = final temperature - initial temperature

 = 37.0 - 5.0 = 32.0 degree C

m = ?

q = 20.0 J

Let's plug in the values in the formula:

m = 0.15 g

So, the mass of water for the given problem is 0.15 g.

catya that's not even a b or c