Which of the following laboratory procedures best illustrates the law of conservation of mass? reacting 12 g of c with 32 g of o2 to form 44 g of co2 and unused reactants weighing 100 g of cu powder and 100 g of fe filings heating 100 g of caco3 to produce 56 g of cao dissolving 10 g of nacl in 100 g of water

The correct statement is reacting 12 g of C with 32 g of to form 44 g of and unused reactants.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed, but it can only be transformed from one form to another. The total mass in the reaction remains constant.

From the given options:

The equation for this is given by:

Mass on the reactant side = (12 + 32)g = 44 g

Mass on the product side = 44 g

Hence, this equation follows Law of Conservation of mass.

As, there is no equation formed, so there will be no chemical reaction and will not follow, law of conservation of mass.

The equation for this is given by:

Mass on the reactant side = 100 g

Mass on the product side = (56 + 0)g = 56g

Hence, this equation does not follow Law of Conservation of mass.

As, salt is getting dissolved in water and hence, it is a physical change and will not follow law of conservation of mass.

Therefore, the correct statement is reacting 12 g of C with 32 g of to form 44 g of and unused reactants.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer