Chemistry, 04.07.2019 22:30 moneykingmarco079

Given licl, nacl, kcl, mgcl2, and srcl2, arrange the compounds in order of increasing lattice energy.

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Answer from: xojade

The order of the given compounds in their increasing lattice energy is as follows:

$\boxed{{\text{KCl}} < {\text{NaCl}} < {\text{LiCl}} < {\text{SrC}}{{\text{l}}_2} < {\text{MgC}}{{\text{l}}_{\text{2}}}}$

Further explanation:

Lattice energy:

The amount of energy released when ions are combined to form an ionic compound or the energy required to break the ionic compound into its constituent gaseous ions is known as lattice energy. It can have positive and negative values. It cannot be measured directly and therefore is denoted by $\Delta {{\text{H}}_{{\text{lattice}}}}$ .

Factors on which lattice energy depends:

1. Charge on ions: It is directly related to the lattice energy. High charges on the ions increase the electrostatic forces of attraction and therefore lattice energy also increases.

2. Size of ions: It is inversely related to the lattice energy. As the ionic size increases, the distance between the nuclei also increases and therefore lattice energy decreases.

LiCl, NaCl, and KCl have the same anion $\left( {{\text{C}}{{\text{l}}^ - }} \right)$ . The charges on Li, Na, K are also same (+1). So the lattice energy is decided by the size of the ions. Li, Na, and K are present in the same group of the periodic table. Li is present above Na and Na is present above K. The size of Li-ion is the smallest and that of K ion is the largest. Therefore, the lattice energy of LiCl is the highest, followed by NaCl and KCl will have the least lattice energy among these three compounds.

${\text{MgC}}{{\text{l}}_2}$ and ${\text{SrC}}{{\text{l}}_2}$ also have the same anion $\left( {{\text{C}}{{\text{l}}^ - }} \right)$ . But these cations have higher charges than those of LiCl, NaCl, and KCl so their lattice energies are higher. The size of Mg is smaller than that of Sr so the lattice energy of ${\text{MgC}}{{\text{l}}_2}$ will be more than that of ${\text{SrC}}{{\text{l}}_2}$ .

The resultant order of the given compounds in their increasing lattice energy is as follows:

${\text{KCl}} < {\text{NaCl}} < {\text{LiCl}} < {\text{SrC}}{{\text{l}}_2} < {\text{MgC}}{{\text{l}}_{\text{2}}}$

Learn more:

1. Identify the exothermic change: link

2. Ranking of elements according to first ionization energy: link

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Solid state

Keywords: lattice energy, LiCl, NaCl, KCl, MgCl2, SrCl2, anion, Cl-, size of ions, charge on ions¸ increase, decrease.

Answer from: Quest

Cr(oh)3 -> cr(3+) + 3oh-

Answer from: Quest

dynamic equilibrium is the answer.

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