Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds. electronegativity difference of na and f: yes no

Yes, sodium and fluorine form ionic bonds.

Explanation:

Electronegativity of sodium (Na) is 0.93.

Electronegativity of fluorine (F) is 3.98.

Electronegativity difference of Na and F will be calculated as follows.

   Electronegativity difference = Electronegativity of F - Electronegativity of Na

                                                   = 3.98 - 0.93

                                                   = 3.05

Thus, difference in electronegativity greater than 1.5 to 1.7, hence, bond between sodium and fluorine is ionic.

imma come back to you hold on

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons