Calculate the standard enthalpy of combustion. the standard enthalpy of formation of sucrose is - 2226.1kj/mol

The question is incomplete, here is the complete question:

Calculate the standard enthalpy of combustion of sucrose. The standard enthalpy of formation of sucrose is -2226.1 kJ/mol

The standard enthalpy of combustion of sucrose is -5636.52 kJ

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

The chemical equation for the combustion of sucrose follows:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

Hence, the standard enthalpy of combustion of sucrose is -5636.52 kJ

where's the diagram?