Compound a, c10h22o, undergoes reaction with dilute h2so4 at 50°c to yield a mixture of two alkenes, b and c, c10h20. the major alkene product, b, gives only 3-pentanone after ozone treatment followed by reduction with zinc in acetic acid. draw the structure of the major alkene product, compound b.

Answer :

When compound A, undergoes reaction with dilute at to yield a mixture of two alkenes, B and C. In these two alkenes B is the major product and C is the minor product.

According to the saytzeff's rule, the more substituted alkene is formed as a major product during dehydration that means double bond is formed due to loss of water molecule. Dilute is act as a dehydrating agent.

Now the major product alkene B gives only 3-pentanone after ozonolysis followed by reduction with zinc in acetic acid.

The reaction is shown below.

i think it is true since you can test the answer and can use observations to complete it.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied