An ideal gas sample with 7.20 atm pressure occupies 250ml voulme at 18•c. what volume would it occupy at 1.50atm and 216•c?

The   volume  of  ideal gas  that would   occupy  at 1.50 atm  and 216 c is

2016.49 ml

calculation

  that is P1V1/T1=  P2V2/T2

 P1( pressure 1) =  7.20  atm

V1 ( volume 1) = 250  ml

T1 ( temperature 1) = 18 + 273=291  K

P2 ( pressure 2) = 1.50 atm

T2 ( temperature 2)= 216+273=489 K

V2  (  volume 2) =?

 V2=[(T2 xP1 x V1)/(T1 xP2)]

V2=[ (489 K  x 7.20 atm  x 250 ml)   / ( 291 k  x 1.50 atm)] =  2016.49  Ml

i do not get it   at all

they vary. it used to be meat, grain, bread, candy, beverages, donuts, and fruits/vegetables. now they added exercise in.