How many calories is required to change the temperature of 2.18g of water from 15.3°c to 69.5°c. the specific heat of liquid water is 1.00cal/g°c.

The number  of calories that are  required  to change the temperature  of 2.18 g of water from 15.3 c to 69.5 c is  118.16 cal

    calculation

 heat is therefore= 2.18 g x 1.00 cal/g/c  x 54.2 c=118.16  cal

Given:

Mass of water, m = 2.18 g

Initial temperature of water, T1 = 15.3 C

Final temperature, T2 = 69.5 C

Specific heat, c = 1.00 cal/gC

To determine:

Heat required to raise the water temperature

Explanation:

The amount of heat, Q, required to raise the temperature of water from T1 to T2 is:

Q = mcΔT = mc(T2-T1)

Q = 2.18 * 1 * (69.5-15.3) = 118.16 cal

Ans: Heat required is 118.16 cal

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