Com relaçao a pilha mg/mg2+//cu2+/cu, indique a: o polo positivo b: o anodo c: a reação global

A: Cu; B: Mg; C: Mg + Cu²⁺ ⟶ Mg²⁺ + Cu

Explanation:

The left-hand side of the cell diagram is where oxidation occurs (the anode).

Mg ⟶ Mg²⁺ + 2e⁻

So, Mg is the anode.

The right-hand side of the cell diagram is where reduction occurs (the cathode)

Cu²⁺ + 2e⁻ ⟶ Cu

As the copper ions hit the copper cathode, they remove electrons from the metal and become copper atoms. Since the metal has lost electrons, Cu is the positive electrode.

To get the overall reaction, we add the two half-reactions,

Mg ⟶ Mg²⁺ + 2e⁻

Cu²⁺ + 2e⁻ ⟶ Cu            

Mg + Cu²⁺ ⟶ Mg²⁺ + Cu

the millers tale is the answer.

indium, and thallium have three electrons i think