What volume of ammonia in liters, at stp, can be produced from 2.0 kg of hydrogen gas, h2, and an excess of nitrogen gas, n2? n2 (g) + 3 h2 (g) → 2 nh3 (g)

Ok so rewrite the equation for yourself :).

N2 + 3H2 -> 2NH3 (Always check if it is balanced).

Ok so we have 2kg of hydrogen conver this to grams and then to moles.
2kg -> 2000g
2000g divide by R.M.M of H2
R.M.M
2H - 2 * 1 -> 2
2000/2 - 1000 moles.
Look at the ratio of H2 to 2NH3.
We see that we get 2NH3 for every H2 therefore the ratio is 1:2.
This means that we HAVE 2000 moles of 2NH3.
At stp. we know that 1 moles = 22.4 Litres
We have 2000 moles that means that we produce 44800 litres of NH3 at stp.
2000 * 22.4 - 44800
Hope this helps :).

It’s b. mass i searched it up