Read the following chemical equation: 2co + 3f2 → 2cof3 which statement best identifies and describes the reducing agent in the reaction? co is the reducing agent because its oxidation number increases. co is the reducing agent because its oxidation number decreases. f2 is the reducing agent because its oxidation number increases. f2 is the reducing agent because its oxidation number decreases.

- (1) Co is the reducing agent because its oxidation number increases.

Explanations:-  The given equation is:

A reducing agent is the one that donate electrons. When electrons are lost from an atom then it's oxidation number increases. So,we could say that the element whose oxidation number increases, get's oxidized and works as a reducing agent.

In elemental state the oxidation number is zero. For the reactant side, cobalt and fluorine are in their elemental form and so the oxidation numbers for both  of these is zero. On product side, the oxidation number of F is -1. Since, there are three F in the product and the over all charge for it is zero, the oxidation number of Co is +3.

Co is oxidized as it's oxidation number is increased from 0 to +3 and it loses three electrons. Fluorine is reduced as it's oxidation number decreased from 0 to -1 and it gain electrons.

Co is electron donor and F is electron acceporr. hence, Co is the reducing agent.

The half equations could also be shown as:

oxidation half equation:-  

reduction half equation:-

reducing agent:-  Co

Oxidizing agent:-

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm