If you mix 25.0 ml of 0.10 m hcl with 0.055g of calcium carbonate, how many moles of hcl are not neutralized by the calcium carbonate

The chemical equation representing the reaction of calcium carbonate with hydrochoric acid is:

Moles of HCl given =

Moles of =

Moles of HCl that would react with :

=0.0011mol HCl

Moles of HCl that would not be neutralized = 0.0025 mol - 0.0011 mol

                                                                        = 0.0014 mol HCl

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )