How many different e2 products can form from the dehydrohalogenation of 2-bromobutane?

We have to get the number of eliminated products formed from dehydrohalogenation of 2-bromobutane.

The number of eliminated products formed from dehydrohalogenation of 2-bromobutane is two. The products are (i) 1-butene and (ii) 2-butene.

In 2-bromobutane, bromine is attached at C-2 position of butane. From 2-bromobutane, proton from β-position gets eliminated and bromide gets released.

There are two β-H atoms with respect to leaving group Br⁻: one H-atom is at C-3 position and other one is at C-1 position.

Hence, two different products are formed on elimination reaction of 2-bromobutane.

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since electrons are negative the answer is neagtaive