Chemistry, 02.07.2019 14:30 barbie8775

How do you write the balanced equation for strontium hydroxide and zirconium (i) perchlorate

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Answer from: lordicy

The law of conservation of mass states that the mass of a system must remain constant everytime, it can neither be created or destroyed. This means the number of atoms of each element on reactant side must equal the number of atoms of each element on product side.

First we figure out the chemical formula for each compound by taking advantage of oxidation states which are able to tell us whether an element will lose or gain an electron

Strontium hydroxide?

Sr is an alkaline earth metal which has 2 valence electrons that when both are lost it has an oxidation state of +2. Since we know the hydroxide ion has a charge of -1, $-_{OH}$ , Then two $-_{OH}$ are needed to form compound, hence we have SrOH_2

zirconium (I) perchlorate?

The oxidation state of zirconium is +1 since it is stated that we have zirconium(I). Converserly, perchlorate has a -1 charge which further proves that zirconium has a +1 oxidation state

The product would have a strontium diperchlorate because we know from earlier that Sr has a +2 oxidation state, and we would also have ZrOH because Zr has a +1 oxidation state and $-_{OH}$ has a -1 charge

The unbalanced equation with all chemicals formulas would be

$SrOH_2_(s) + ZrClO^{-} _4(aq) == Sr(ClO^{-} _4)_2(aq) + ZrOH(aq)$

Using the law of conservation of mass, it is clear that there is 1 molecule of $ClO^{-} _4$ on reactant side as compared to 2 molecules of $ClO^{-} _4$ on product side. On the other hand, the are 2 molecules of $-_{OH}$ on reactant side and 1 molecule of $-_{OH}$ on product side. To balance we add a coefficient of 2 on ZrClO_4 and a coefficient of 2 on ZrOH,

SrOH_2_(s) + 2ZrClO_4_(aq) == Sr(ClO_4)_2_(aq) + 2ZrOH(aq) .

Answer from: Quest

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.

Answer from: Quest

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

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