How many milliliters of a 0.80 m sucrose solution contain each of the following number of grams? the molar mass of sucrose (c12h22o11) is 342.3 g/mol. a. 7.45 g b. 17.0 mg

 The  number of Ml  of 0.80 M sucrose solution  that contain

(A) 7.45 g are  27.25 Ml

 calculation

volume= moles /molarity

molarity = 0.80 M which is the same as  0.80 mol/l

moles=  mass/molar mass

=  7.45 g/ 342.3 g/mol =0.0218 moles

volume is therefore  = 0.0218 moles / 0.80 mol/L=0.02725 L

convert into ml  by multiplying  by 1000

= 27.25  ml

volume  = moles/molarity

molarity =  0.80 M = 0.80 Mol/L

moles =mass/molar mass

mass 17.0 mg convert into  g by diving  by 1000=0.017 g

moles is therefore  = 0.017 g/ 342.3 g/mol = 4.97 x10^-5 moles

volume =  (4.97 x 10^-5 moles)  /0.8  mol /l=6.21 x10^-5 L

= 6.21 x10^-5  x 1000 =0.0621 Ml

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2