What is the change in enthalpy for the following reaction?   2h2o2(aq)    2h2o(l)  + o2(g)  given: h2o:   ∆h= -242 kjh2o2:   ∆h= -609 kja.-286 kjb.  -572 kjc.  572 kjd.  286 kj

The given chemical reaction is:

The standard heats of formation of are:

Δ) = -285.8kJ/mol[/tex]

Δ) = -187.6 kJ/mol[/tex]

Calculating the change in heat:

Δ=∑ΔH-∑ΔH

                         = [{2 * (-285.8 kJ/mol)} -{2*(-187.6 kJ/mol)}]

                          = -196.4 kJ/mol

Therefore, the change in enthalpy for the given reaction is -196.4 kJ/mol

acid rain does not usually kill trees directly. instead, it is more likely to weaken the trees by damaging their leaves, limiting the nutrients available to them, or poisoning them with toxic substances slowly released from the soil. the main atmospheric pollutants that affect trees are nitrates and sulphates.