Asolution containing lead(ii) nitrate is mixed with one containing sodium bromide to form a solution that is 0.0140 m in pb(no3)2 and 0.0024 m in nabr. what is the value of q for the insoluble product? express the reaction quotient to three significant figures.

Explanation:

Since all sodium salts and all nitrates are soluble, the insoluble product must be lead(II) bromide.

The equation for the equilibrium is

                     PbBr₂ ⇌ Pb²⁺  +  Br⁻

I/mol·L⁻¹:                    0.0140  0.0024

= [Pb²⁺][Br⁻]²

[Pb²⁺] = 0.0140 mol·L⁻¹

[Br⁻] = 0.0024 mol·L⁻¹

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j